x^2-22x-240x=0

Solution for x^2-22x-240x=0 equation:

x^2-22x-240x=0

We add all the numbers together, and all the variables

x^2-262x=0

a = 1; b = -262; c = 0;
Δ = b2-4ac
Δ = -2622-4·1·0
Δ = 68644
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{68644}=262$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-262)-262}{2*1}=\frac{0}{2}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-262)+262}{2*1}=\frac{524}{2}
=262
$